In the last comparator, if the counter value is equal to 12, the timer will start to run for 5sec and after 5sec it will turn OFF all the outputs.ħ. Consider 3 conveyers, if I switch ON the switch SW1 then the first 2 conveyers will turn ON.In the third comparator, if the counter value goes greater than or equal to 9, then the output Q100.02 will turn ON.In the second comparator, if the counter value goes greater than or equal to 6, then the output Q100.01 will turn ON.In the first comparator, if the counter value is greater than or equal to 3, then the output Q100.00 will turn ON.We are using comparators to compare the counter value.Switch 1 is used to give the counts to the counter.CNTR 000 #12 – Up Down Counter for 12 counts.When the counter reaches 12 counts all the outputs will turn OFF after 5sec.Output Q3 should be ON when the counter value is greater than 9,.Output Q2 should be ON when the counter value is greater than 6,.The output Q1 should be ON when the counter value is greater than 3,.Write a logic for the outputs Q1, Q2 and Q3 to turn on/off In the last comparator, if the counter value is greater than or equal to 6, then the timer T2 will turn ON and after 10sec both the outputs Q100.00 and Q100.01 will turn OFF.Ħ.In the second comparator, if the counter value is greater than or equal to 4, then the output Q100.01 will turn after 5sec using the timer T1.In the first comparator, if the condition satisfies that is if counter value is greater than or equal to 2, then the output Q100.00 starts blinking using the timer T0.Switch 1 is used to give the counts to the counter C1, and switch 3 to reset the counter.TIM 002 #100 – On Delay Timer for 10sec.CNTR 000 #6 – Up Down Counter for 6 counts.After 6 counts both outputs get OFF after 10sec, using a counter comparator.when switch S1 is ON After 2 counts Q1 blinks,.In order to turn OFF the outputs we are using output interlocking concept.In the last condition, if all the switches are ON switch 1 and switch 2 and switch 3 are ON then only Hazard Mode output should be ON.In the second condition, if any two switches are turned ON it may be switch 1 and switch 2 OR switch 2 and switch 3 OR switch 3 and switch 1 only Stop Mode output should be ON.In this problem if any one of the switch is turned ON, it may be switch 1 or switch 2 or switch 3 only Run Mode output should be turned ON.In this problem we are using output interlocking concept.Q100.02 – Alarm Siren Sounds (Hazard Mode).If any three inputs are on, am alarm siren sounds.If any two inputs are on, the red pilot light goes on.If one input is on, the green pilot light goes on, nothing happens.There are three hazard inputs to the alarm systems that go on as some operational malfunction occurs. If any one of the stop button is turned ON the conveyor will stop.ģ.
#CONTADOR OMRON CX PROGRAMMER SERIES#
To turn OFF the output Q100.00 we have to use RST coil, hence I0.01 Stop Button connected to the RST coil Output with address Q100.00.Ģ.Start button I0.00 is a Push button and it gives a pulse signal to the right side rung hence by using the SET coil we can hold the output Q100.00 in the high state, and it will be in ON state until it reset.When we are using the push button either we need to use latch to hold the output or else we can use SET and RST coil function. I0.00, I0.01 are the inputs considered as Start and Stop Button. b) Write the same ladder logic without latches.
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